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A 3kW oven supplied with 9kJ of energy. How many seconds can it be run for

User Cadrian
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The energy consumption rate of the oven is
3 kW = 3000 W = 3000 J/s.

The amount of energy supplied is
9 kJ = 9000 J

The time that the oven will run is

t= (9000 \, J)/(3000 \, J/s) = 3 \, s
(9000 J)/(3000 J/s) = 3 s

Answer: 3 seconds
User Nischay Goyal
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