Q = m*Cp*(del T)
Where m = mass cp = specific heat capacity = 4.1855 J g–1 K–1 at 15 deg C del T = temp change = 14.5-15.5 = - 1 deg C
there fore, Q = 10*4.1855*-1 = - 41.855 J
Hence 42 joules will be release by water when temp is decrease from 15.5 to 14.5 deg C