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Please help me, Engineering.

Please help me, Engineering.-example-1
User Ritu
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1 Answer

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Answer:

15. R = R₁ + R₂ + R₃

16.
R = (1)/(R_1) +(1)/(R_2) = (R_2 + R_1)/(R_1 \cdot R_2)

Step-by-step explanation:

15. The equation for the sum of resistances arranged in series is given as follows;


R_(Network) (Series) = R₁ + R₂ + R₃ + ... +
R_N

Therefore, the equation for the total resistance, 'R' of 3 series resistors is given as follows;

R = R₁ + R₂ + R₃

Where;

R₁, R₂, and R₃ are the three resistances arranged in series

16. The equation for the sum of resistances arranged in parallel is given as follows;


R_n = (1)/(R_1) + (1)/(R_2) + (1)/(R_3) + ... + (1)/(R_n)

Therefore, the total resistance, R, of two resistance arranged in parallel is given as follows;


R = (1)/(R_1) +(1)/(R_2) = (R_2 + R_1)/(R_1 \cdot R_2)

User PixelToast
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