Question

4sin theta + 3 square root of 3 = square root of 3

Answer 1

Solving for θ:

4sinθ + 3√3 = √3

First subtract 3√3 from both sides:

4sinθ = -2√3

Now, divide by 4:

sinθ = (-2√3)/4
sinθ = -√3/2

Using the unit circle we know that sin of -√3/2 is 240° or 4/3π and 300° or 5/3π

Hope this helps!