y=1/5x+5 with the point (-6, 0)
The line perpendicular to this line will have a slope that's the negative reciprocal of this one. So if the slope here is 1/5 (based on y=mx+b, where m is the slope), then the perpendicular slope would be -5/1.
So now that you have the point and the slope, use the point-slope formula.
y - y₁ = m(x - x₁)
m = -5
(x₁, y₁) = (-6, 0)
y - 0 = -5(x + 6)
y = -5x - 30
y = -5x - 30 is the line perpendicular to y=1/5x+5.