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Which expressions are equivalent to the one below? Check all that apply.

log 2 - log 6

User Terafor
by
7.0k points

2 Answers

3 votes
There are no correct expressions listed.

Log(2) - log(6) is equivalent to

log(1/3)
or
-log(3)
or
-0.47712...
or
any one of a bunch of others.
User Ralien
by
7.3k points
3 votes

Answer:

Given the expression: log 2 -log 6

Use the logarithmic rule :


\log((m)/(n)) = \log m - \log n


\log x^n = n\log x

Use the above rule to solve the expression:


\log 2 -\log 6 = \log (2)/(6) = \log (1)/(3) [∴
\log((m)/(n)) = \log m - \log n ]

or


\log 2 -\log 6 =\log 2+ \log 6^(-1) = \log 2 + \log (1)/(6) [∴
\log x^n = n\log x ]

or

value of : log 2 -log 6 = 0.30102999566 - 0.77815125038 = -0.47712125472



User Carrie Hall
by
7.1k points