Question

Solve M=h-w/8 for the variable H

Solve the above equation for W

Solve w=x+y/z for y


Solve the equation above for z

The formula for area of a triangle is A=1/2b solve this equation for B

Solve the equation P=kt/v for the letter K

Answer 1

1) m = h - w/8

Subtract h from both sides.

m - h = -w/8

Subtract m from both sides.

-h = -m - w/8

Divide all terms by -1.

h = m + w/8.

2) m = h - w/8

Get rid of the denominator 8 by multiplying 8/1 to all terms.

8m = 8h - w

Add w on both sides and subtract 8m from both sides.

w = 8h - 8m

3) w = x + y/z

Get rid of the denominator z by multiplying it to all terms.

wz = xz + y

Subtract xz from both sides of the equation.

wz - xz = y OR y = wz - xz

4) w = x + y/z

Subtract x from both sides.

w - x = y/z

Get rid of the denominator by multiplying it to all terms.

wz - xz = y

Now factor the expression wz - xz.

z(w - x) = y

Divide both sides by w - x.

z = y / w - x

This is read as z equals to y divided by w minus x.

5) The area of a triangle is A = 1/2bh

First, get rid of the denominator by multiplying both sides by 2.

2A = bh

To find b, divide both sides by h.

2A/h = b

6) P = kt/v

Multiply both sides by v.

Pv = kt

Divide both sides by t.

Pv/t = k OR k = Pv/t.

Answer 2

Explanation:

(1) M = h -
`(w)/(8)`

h = M +
`(w)/(8)`

(2) M = h -
`(w)/(8)`

M - h = -
`(w)/(8)`

`(w)/(8)` = h - M

w = 8(h - M)

(3) w = x +
`(y)/(z)`

(w-x) =
`(y)/(z)`

`(z)/(y)` =
`(1)/((w-x))`

z =
`(y)/(w-x)`

(5) Area of triangle A =
`(1)/(2)b`

b = 2A

(6)
`P=(kt)/(v)`

⇒ PV = kt

⇒ k =
`(PV)/(t)`