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N equation of a line through (0, 2) which is perpendicular to the line y=3x+3y=3x+3 has slope

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Something's not quite right here. What do you mean by "N?"

I could and will make assumptions regarding what you meant. (Feel free to correct me if need be.)

Find the equation of a line through (0,2) which is perpendicular to the line y=3x+3. To find the slope of this perpendicular line, take the negative reciprocal of 3 (the slope of the given line). It is -1/3.

Using the point-slope form of the equation of a straight line:

y = (-1/3)x + 2 (answer)
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