Question

`8x^2+16x+8`Find the real/complex root of 8x^2+16+8

Answer 1

Consider the polynomial:

`8x^2+16x+8`

now, to find the roots of the above equation, use the following quadratic equation:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

in this case, we have that a = 8, b = 16 and c = 8. So, replacing the above data on the previous equation we get:

`x=\frac{-16\pm\sqrt[]{16^2^{}-4(8)(8)}}{2(8)}`

this gives us :

`x\text{ = }-1`

thus, we can conclude that the root of the given polynomial is

`x\text{ = }-1`