Question

Solve x ym = y x3 for m.

Answer 1

xym-yx3m = 0
xym (1-1x2) = 0
xym (1 (un cuadrado)-1x2)=0
xym(1+x)(1-x)=0
1+x=0
1-x=0
m= 0
x=-1
x=1
Is true
m=0;x= -1;1