Question

15.Solve the given equation over the interval [0, 2x): 6 tan2 x + 13 tan x + 6 = 0.0x=tanand x=tan32x=-- and x=32x = -0.983 and x = 1 - 0.588 and x = 2.11 - 0.983 and x = 2.0 - 0.588x = -0.588 and x = -0.983

Answer 1

The answer is

x = tan-1 (-2/3)

x = tan-1 (-3/2)

SOLUTION

we can substitute tan x with variable y

we will have a quadrat