Question

1. Which procedure could be used to graph the line represented by the following equation? Y=1/2x+3

A. Plot the x-intercept (3,0) and use the slope of 1/2 to find a second point.
B. Plot the Y-intercept (0,3) and use the slope of 1/2 to find a second point
C. Plot the X-intercept (1/2,0) and use the slope of 3 to find a second point.
D. Plot the Y-intercept (0,1/2) and use the slope of 3 to find a second point

Answer 1

we have

`y=(1)/(2)x+3`

we know that

the slope m of the line is equal to

`m=(1)/(2)`

Find the x-intercept

The x-intercept is the value of x when the value of y is equal to zero

so

For
`y=0` find the value of x

`0=(1)/(2)x+3`

`x=-6`

The x-intercept is the point
`(-6,0)`

Find the y-intercept

The y-intercept is the value of y when the value of x is equal to zero

so

For
`x=0` find the value of y

`y=(1)/(2)*0+3`

`y=3`

The y-intercept is the point
`(0,3)`

therefore

the answer is the option

B. Plot the Y-intercept (0,3) and use the slope of 1/2 to find a second point