Question

What is the period, in seconds, of a simple pendulum of length 2 meters? Use the gravitational constant g = 9.8 m/s^2 and round your answer to two decimal places.

Answer 1

2.84 seconds

Explanation:

Answer 2

The period, in seconds to two decimal places is, 2.84 sec

Explanation:

Using formula:

`T = 2 \pi \sqrt{(l)/(g)}` ......[1]

where

T represents the Time period in second

l represents the length of the pendulum/

As per the statement:

Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and
`\pi = 3.14`

Substitute the given values we have;

`T = 2\cdot 3.14 \cdot \sqrt{(2)/(9.8)}`

⇒
`T = 6.28 \cdot \sqrt{(1)/(4.9)}=6.28 \cdot (1)/(2.21359436212)= (6.28)/(2.21359436212) = 2.83701481512`

Therefore, the period, in seconds to two decimal places is, 2.84 sec