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A chemist requires 0.811 mol Na2CO3 for a reaction. How many grams does this correspond to?
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A chemist requires 0.811 mol Na2CO3 for a reaction. How many grams does this correspond to?

User Boumbh
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1 Answer

3 votes
mol=mass in g÷Mr
Mass=mol×Mr
=0.811×(add up mass of all elements)
=0.811×(16×3+23×2+12)
=85.966g
User CJ Dennis
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