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What are the roots of x in -10x^2 + 12x - 9=0

2 Answers

5 votes

Answer:

k=-11

Explanation:

Correct for plato

User Pockets
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The "roots" of a function are the values of x for which y is zero. To solve this, be must use the quadratic formula, where a= -10, b=12, and c=-9
Quadratic formula:
x= [-b +/- √(b²-4ac)] ÷ 2a
Plugging in a, b, and c:
x= (-12 +/- √144 - 4(-10)(-9)) ÷ -20
x= (-12 +/- √(144 + 360)) ÷ -20
x = (-12 +/- 6√14) ÷ -20
x = (-12 + 6√14)/-20 or (-12 - 6√14)/ -20
x = 3/5 +/- 3√(14) / 10
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