Final answer:
To prepare 100 mL of a 0.15 M NaOH solution, you will need approximately 0.60 g of NaOH.
Step-by-step explanation:
To calculate the mass of NaOH needed to prepare a 0.15 M solution, we need to use the formula:
Mass (g) = Molarity (M) x Volume (L) x Molar Mass (g/mol)
In this case, the molarity is 0.15 M and the volume is 100 mL (or 0.1 L). The molar mass of NaOH is 22.990 + 15.999 + 1.008 = 39.997 g/mol.
Mass (g) = 0.15 M x 0.1 L x 39.997 g/mol = 0.5999 g, which can be rounded to 0.60 g.