60.0k views
1 vote
How do you find the x and y intercepts of x^2+x-2/x^2-3x-4?

User Adi Mor
by
8.0k points

1 Answer

3 votes
First equal the equation to f(x) or y

f(x)= (x²+x-2)÷(x²-3x-4)

To find y-intercept, x coordinates have to be 0

f(0)=(0²+0-2)÷(0²-3(0)-4)
f(0)=-2/-4
f(0)=1/2 (y-intercept)

To find x-intercept, make y=0

0=(x²+x-2)÷(x²-3x-4)
0((x²-3x-4)=(x²+x-2)
0=x²+x-2
0=(x-1)(x+2)
x-1

x-1=0
x=1

x+2=0
x=-2

The x-intercepts would be 1, -2

Hope I helped :)


User MANJEET
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories