Question

HELP please I have a bunch of these and I’m stressing cause I have like 50 tests tomorrow

Answer 1

the idea being, the notation is for a "serie" or sequence.

f(n-1) simply means, "the value of the term before the current one", whilst "n" is the current term.


`\bf \begin{array}{llll} term&value\\ ------&------\\ f(1)&-3\\\\ f(\stackrel{n}{2})&4[f(\stackrel{n}{2}-1)]+3[f(\stackrel{n}{2}-1)]\\ &4[f(1)]+3[f(1)]\\ &4(-3)+3(-3)\\ &-21\\\\ f(\stackrel{n}{3})&4[f(\stackrel{n}{3}-1)]+3[f(\stackrel{n}{3}-1)]\\ &4[f(2)]+3[f(2)]\\ &4(-21)+3(-21)\\ &-147\\\\ \end{array}`



`\bf \begin{array}{llll} &\\ ~~~~~~~~~~~~&~~~~~~~~~~~~\\ f(\stackrel{n}{4})&4[f(\stackrel{n}{4}-1)]+3[f(\stackrel{n}{4}-1)]\\ &4[f(3)]+3[f(3)]\\ &4(-147)+3(-147)\\ &-1029\\\\ f(\stackrel{n}{5})&4[f(\stackrel{n}{5}-1)]+3[f(\stackrel{n}{5}-1)]\\ &4[f(5)]+3[f(4)]\\ &4(-1029)+3(-1029)\\ \end{array}`

Answer 2

ok so what you want to do is replace the n with whatever number is in the parenthesis next to the f