Question

Help me please! |-.-| The struggle is real...

2x^2-13x+4=0
solve using the quadratic formula

Answer 1

`\bf \qquad \qquad \textit{quadratic formula}\\\\ \begin{array}{llccll} y=&{{ 2}}x^2&{{ -13}}x&{{ +4}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array} \qquad \qquad x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}} \\\\\\ x=\cfrac{-(-13)\pm√((-13)^2-4(2)(4))}{2(2)}\implies x=\cfrac{13\pm√(169-32)}{4} \\\\\\ x=\cfrac{13\pm√(137)}{4}\implies x\approx \begin{cases} 6.17617497768\\ 0.32382502232 \end{cases}`