74.3k views
5 votes
Find cubic function given the zeroes 3, -4, and 6

1 Answer

4 votes

\mathsf{(x-3)\cdot(x+4)\cdot(x-6)=0}\\ \\ \mathsf{(x^2+4x-3x-12)\cdot(x-6)=0}\\ \\ \mathsf{(x^2+x-12)\cdot(x-6)=0}\\ \\ \mathsf{x^3-6x^2+x^2-6x-12x+72=0}\\ \\ \boxed{\mathsf{x^3-5x^2-18x+72=0}}
User Max Fomin
by
7.6k points

No related questions found