Solution:
Given:
[tex]\begin{gathered} Quadrilateral\text{ PUMA} \\ PU
The quadrilateral can be sketched as shown;
Since PU < UM, then it can not be a square.
Since PM is a diameter, and PU < UM, then it can not be a rectangle.
Hence, it is an isosceles trapezoid.
Two right angles can exist in an isosceles trapezoid and might also not exist. Hence this is not always true.
The angles A and U are supplementary because opposite angles of a cyclic quadrilateral are supplementary.
There are obtuse angles and acute angles in the quadrilateral. Hence, PUMA does not have four acute angles.
Therefore, the statements that are always true from the description are: