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What is the midpoint of AB if A = (−2, 2) and B = (3, −1)? A. (1/2,1/2) B. (5/2,3/2) C. (-1/2.-1/2) D. (-5/2,-3/2)

What is the midpoint of AB if A = (−2, 2) and B = (3, −1)? A. (1/2,1/2) B. (5/2,3/2) C. (-1/2.-1/2) D. (-5/2,-3/2)
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What is the midpoint of AB if A = (−2, 2) and B = (3, −1)?

A. (1/2,1/2)
B. (5/2,3/2)
C. (-1/2.-1/2)
D. (-5/2,-3/2)

User MateodelNorte
by
7.4k points

1 Answer

3 votes
midpoint formula (x1 + x2) / 2, (y1 + y2)/2
(-2,2)...x1 = -2 and y1 = 2
(3,-1)...x2 = 3 and y2 = -1
now we sub
m = (-2 + 3) / 2 , (2 - 1) / 2
m = (1/2, 1/2) <===
User Hanna Khalil
by
7.8k points
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