Find the solution to the initial value problem (1 + x^{5}) y' + 5 x^{4} y = 5 x^{8}

asked Jul 10, 2018 82.6k views

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$\bigg((1+x^5)y\bigg)'=5x^8$

$(1+x^5)y=5\displaystyle\int x^8\,\mathrm dx$

$(1+x^5)y=\frac59x^9+C$

y=(5x^9+C)/(9(1+x^5))

Webbyfox answered Jul 15, 2018

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