Question

An exceptional standing jump would raise a person 0.79 m off the ground. to do this, what force must a 79 kg person exert against the ground? assume the person crouches a distance of 0.19 m prior to jumping, and thus the upward force has this distance to act over before he leaves the ground.

Answer 1

Given:

Mass of a person, m =79 kg
Distance, d = (0.79 m + 0.19 m) = 0.98 m

Required: Force, F

Solution:

Working Formula:

Force = weight x distance
F = w x d

where: w = mass x gravitational force
d = distance

F = (79)*(9.81)*(0.98) = 759.5 Joules

ANSWER: 759.5 Joules