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How many grams of caf2 would be needed to produce 1.29 moles of f2?

User Cienki
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2 Answers

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Answer is: 100.72 grams of calcium fluoride.

Balanced chemical reactions:

1) CaF₂ + H₂SO₄ → 2HF + CaSO₄.

2) 2HF → F₂ + H₂.

1) From chemical reaction 2: n(F₂) : n(HF) = 1 : 2.

n(HF) = 2 · 1.29 mol.

n(HF) = 2.58 mol.

2) From chemical reaction 1: n(HF) : n(CaF₂) = 2 : 1.

n(CaF₂) = 2.58 mol ÷ 2.

n(CaF₂) = 1.29 mol; amount of substance.

m(CaF₂) = n(CaF₂) · M(CaF₂).

m(CaF₂) = 1.29 mol · 78.08 g/mol.

m(CaF₂) = 100.72 g.

User Pengchy
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8.2k points
5 votes
*Given:
1.29 moles F2

*Information needed in calculation
CaF2 molar mass - 78.07 g/mol
F2 molar mass - 38.00 g/mol

*Solution



How many grams of caf2 would be needed to produce 1.29 moles of f2?-example-1
User Anthony Awuley
by
8.2k points