377,061 views
31 votes
31 votes
If 8x = sec θ and 8/x= tan 0. Find the value of 16(x^2 - 1/x^2)​

If 8x = sec θ and 8/x= tan 0. Find the value of 16(x^2 - 1/x^2)​-example-1
User LynnH
by
2.4k points

1 Answer

25 votes
25 votes
If sec 0 = 8x then tan 0 = 8/x ( x does not equal to 0), than the value of 16 ( x squared - 1/x squared) is: 1/4

Answer: 1/4