127k views
2 votes
What are the real roots of 2x^3-42x-40

User Genxgeek
by
8.4k points

1 Answer

2 votes
2x^3-42x-40=0
2x^3-42x=40
2x(x^2-21)=40
a. 2x=40=>x=20
b. x^2=21+40=>x^2=61=>x=+-(radical(61)
User Bryan Larsen
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories