Question

`3/2y+12=7/5y-20`

Answer 1

`\bf \cfrac{3}{2y}+12=\cfrac{7}{5y}-20\impliedby \begin{array}{llll} \textit{now, let's multiply both sides by 10y}\\ \textit{thus, getting rid of the denominators} \end{array} \\\\\\ 10y\left( \cfrac{3}{2y}+12 \right)=10y\left( \cfrac{7}{5y}-20 \right)\implies 15+120y=14+200y \\\\\\ 1=200y-120y\implies 1=80y\implies \boxed{\cfrac{1}{80}=y}`