Question

How is the protein created from the mRNA sequence which reads AUGAUAGUGUAC different from the protein created from one that reads AUGAUAGUGUAG?

U



C



A



G







UUU

Phenylalanine

UCU

Serine

UAU

Tyrosine

UGU

Cysteine

U

U

UUC

Phenylalanine

UCC

Serine

UAC

Tyrosine

UGC

Cysteine

C



UUA

Leucine

UCA

Serine

UAA

Stop

UGA

Stop

A



UUG

Leucine

UCG

Serine

UAG

Stop

UGG

Tryptophan

G



CUU

Leucine

CCU

Proline

CAU

Hisitidine

CGU

Arginine

U

C

CUC

Leucine

CCC

Proline

CAC

Hisitidine

CGC

Arginine

C



CUA

Leucine

CCA

Proline

CAA

Glutamine

CGA

Arginine

A



CUG

Leucine

CCG

Proline

CAG

Glutamine

CGG

Arginine

G



AUU

Isoleucine

ACU

Threonine

AAU

Asparagine

AGU

Serine

U

A

AUC

Isoleucine

ACC

Threonine

AAC

Asparagine

AGC

Serine

C



AUA

Isoleucine

ACA

Threonine

AAA

Lysine

AGA

Arginine

A



AUG

Methionine/Start

ACG

Threonine

AAG

Lysine

AGG

Arginine

G



GUU

Valine

GCU

Alanine

GAU

Aspartate

GGU

Glycine

U

G

GUC

Valine

GCC

Alanine

GAC

Aspartate

GGC

Glycine

C



GUA

Valine

GCA

Alanine

GAA

Glutamate

GGA

Glycine

A



GUG

Valine

GCG

Alanine

GAG

Glutamate

GGG

Glycine

G

a. The first has fewer amino acids than the second.
b. The first has isoleucine where the second has leucine.
c. The first has one more amino acid than the second.
d. The first has serine where the second has valine.

Answer 1

im gonna keep it short... the answer is C

Step-by-step explanation:

Answer 2

C option is the right answer which states teat the first has one more amino acid than the second.

Step-by-step explanation:

The first mRNA sequence codes for the Methionine (start codon), isoleucine, valine, and tyrosine.

The second mRNA sequence for the Methionine, isoleucine, valine only, because the last sequence (UAG) is of stop codon and stop codon do not code for any of the amino acids.