Question

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A coat hanger is in the shape of isosceles triangle ABC shown in the figure. Sides AB and BC are congruent.

if m<BAC=22, then m<ABC= ?

Answer 1

m<BAC = m<BCA = 22
m<ABC = 180 - 2(22)
m<ABC = 180 - 44
m<ABC =136

Answer 2

Answer: m∠ABC=136°

Explanation:

In the given figure we have a coat hanger is in the shape of isosceles triangle ABC.

Sides AB and BC are congruent.

The isosceles theorem says that the angles opposite to the equal sides of a triangle are equal.

Therefore, in ΔABC, we have

m∠BAC=m∠BCA

If m∠BAC=22°, then m∠BCA= 22°

By angle sum property , we have

m∠BAC+m∠BCA+m∠ABC=180°

⇒22°+22°+m∠ABC=180°

⇒m∠ABC+44°=180°

⇒m∠ABC=180°-44°=136°

⇒m∠ABC=136°

Therefore, If m∠BAC=22°, then m∠ABC=136°