Final answer:
To calculate the number of moles of O2 required to react completely with 14.8 mol Al, you can use the balanced chemical equation. In this case, 22.2 mol of O2 are required.
Step-by-step explanation:
To determine the number of moles of O2 required to react completely with 14.8 mol of Al, we need to use the balanced chemical equation for the reaction.
The balanced equation is: 2 Al + 3 O2 → 2 Al2O3
From the balanced equation, we can see that 2 moles of Al react with 3 moles of O2.
Therefore, in this reaction, 1 mole of Al reacts with 3/2 moles of O2.
Given that we have 14.8 mol of Al, we can calculate the number of moles of O2 required:
Number of moles of O2 = (14.8 mol Al) * (3/2 mol O2/1 mol Al) = 22.2 mol O2