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In the pulley system shown below, a 360 N weight is slowly lifted. Assuming the system is 100% efficient and each pulley is weightless, what is the minimum input force needed to lift the weight? Rope Pile L= 16.74m

A. 61 N
B. 121 N
C. 181 N
D. 361 N

User Northpole
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2 Answers

6 votes

Answer:

A. 61 N

Step-by-step explanation:

In this system, there are three moveable pulleys. In this case, the rope will have to move six times as far as the weight will rise. In other words, the input distance is 6 times the output distance ( d in =6⋅ d out ) . Because the efficiency is 100%, the work input is equal to the work output, so we have:

work input = work output

f( in) ⋅ d( in) = f( out) ⋅ d( out)

f( in) ⋅ (6 ⋅ d( out)) = f( out) ⋅ d( out)

f( in) ⋅ 6 = f( out)

f( in) ⋅ 6 = 360 N

f( in) = 60 N

Another way to think of this is that since the rope has to move 6 times as far as the height of the weight, the mechanical advantage will be 6. Therefore, the input force needed is 360 ÷ 6 = 60 N . Of course, 60 N will balance the object, so a force slightly greater than 60 N (like 61 N) will be required to lift it.

User Andrey Yaskulsky
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6.9k points
5 votes
your answer is D. 361 N
User Akshay Anurag
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6.1k points