Question

What is the blood resistivity if a 9.0 v potential difference causes a 240 μa current through the blood in the vein?

Answer 1

The blood resistivity is 37.5 kiloohms.

Step-by-step explanation:

To calculate the blood resistivity, we can use Ohm's Law, which states that the current flowing through a conductor is equal to the voltage across it divided by the resistance of the conductor. In this case, the voltage is 9.0 V and the current is 240 μA (or 0.240 mA).

Using Ohm's Law, we can rearrange the equation to solve for the resistance: R = V/I. Plugging in the values, we get R = 9.0 V / 0.240 mA = 37.5 kΩ (kiloohms).

Therefore, the blood resistivity is 37.5 kiloohms.

Answer 2

38k ohms The conductor in this case may be biological, but knowledge of biology isn't needed to solve the problem. Using ohm's law I = V/R we can calculate any of the 3 values, when given the other 2. First, substitute the known values into the formula. I=V/R 0.000240 = 9 / R Now solve for R. First, multiply both sides by R 0.000240 R = 9 And divide both sides by 0.000240 R = 37500 So the blood resistivity in this example is 37500 ohms. Rounding to 2 significant figures gives 38k ohms.