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In the equation 3x+3y+3z=18 what does x equal

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3x+3y+3z=18

Start by subtracting both sides by 3z

3x + 3y = 18 - 3z

Now , you can subtract 3y from both sides....

3x = - 3z - 3y + 18

Finally .... To get x by itself divide both sides by 3.......

x = - z - y + 6 is the answer
User Perran Mitchell
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