EC bisects so m<BEC = m<CED
11x - 12 + 2(4x + 1) = 180
11x - 12 + 8x + 2 = 180
19x - 10 = 180
19x = 190
x = 10
m<AEB= 11x - 12 = 11(10) - 12 = 98
m<CED = 4x+1 = 4(10) + 1 = 41
m<BEC = m<CED = 41
so
m<AEC = m<AEB + m<BEC
m<AEC = 98 + 41
m<AEC =139
answer
m<AEC =139