Answer:
(−6, 0) , (−1, −2) and (−5, −1)
Explanation:
The given inequality is x+3y ≥ −8
Substitute all the given points in this inequality and check which points satisfy.
For (−6, 0)
-6+3(0) ≥ −8
- 6 + 0 ≥ −8
- 6 ≥ −8 => True.
Hence, (−6, 0) is a solution.
For (−1, −2)
-1 + 3(-2) ≥ −8
-1 - 6 ≥ −8
- 7 ≥ −8 => True.
Hence, (−1, −2) is a solution.
For (−5, −1)
-5 + 3 (-1) ≥ −8
- 5 -3 ≥ −8
-8 ≥ −8=> True.
Hence, (−5, −1) is a solution.
For (−16, 2)
-16 +3 (2) ≥ −8
-16 + 6 ≥ −8
-10≥ −8 => False.
Hence,(−16, 2) is not a solution.
For (0, -3)
0 + 3(-3) ≥ −8
-9 ≥ −8=> False.
Hence, (0, -3) is not a solution.
Therefore, below ordered pairs are solutions of the given inequality
(−6, 0) , (−1, −2) and (−5, −1)