Question

If log3⁡⁡(4y−1)=log3⁡⁡(2y+7), what is the value of y?

Enter your answer as a number, rounded to one decimal place, if necessary, like this: 42.5

Answer 1

Knowing that there are two logs on both sides of the brackets, they cancel out.
This leaves:

4y-1=2y+7 (solve for y)
4y-2y=7-1
2y=6
y=3

Hope this helped :)