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investment historically have doubled every 9 years if you start with $2000 investment how much money would you have after 45 years

User Tedtoal
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2 Answers

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First you would divide 45 by 9 to see how many times it will double which gives you 5. Then, you would multiply 2000 by 2^5 (or just 2000x2x2x2x2x2) to get $64000
User Darcamo
by
6.2k points
3 votes

Answer: $64000

Explanation:

The exponential equation for growth in function with growth factor 'b'in time 't' is given by :-


y=Ab^x , where A is the initial value.

Given : The initial value :
A=\$2000

Growth rate =
b=2\text{ every 9 years}

Time periods in 45 years :
t=(45)/(9)=5

Then , the exponential equation for growth for t=5 is given by :-


y=2000(2)^(5)=64000

Hence, the money you would have after 45 years = $64000

User Johan Soderberg
by
6.8k points
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