Question

A line has a slope of -2/3 and passes through the point -3, 8 what is the equation of the line

Answer 1

y= -2/3 +6 bc...
(-3,8)
y=mx+b
8= -2/3(-3) +b
8=2+b
-2 -2
6=b

Answer 2

`y=-(2)/(3)x+6`

Explanation:

we have been give that

slope, m = -2/3

The line passes through the point (-3,8).

Hence,
`x_1=-3,y_1=8`

The point slope form of a line is

`y-y_1=m(x-x_1)`

Substituting the known values

`y-8=-(2)/(3)(x-(-3))`

On simplifying, we get

`y-8=-(2)/(3)x-2\\\\y=-(2)/(3)x+6`

Thus, equation of line is
`y=-(2)/(3)x+6`