Question

At an arts and crafts fair, a photographer priced a framed print at $49.50. He ended up sellingit for $45.00. Find the percent of decrease in the price of the print. Round the percent to thenearest tenth if necessary.

Answer 1

cost of the framed print = $49.50

selling price = $45.00

decrease = 49.50 - 45.00 = $4.5

Therefore,

`\begin{gathered} \text{percentage decrease=}\frac{\text{decrease}}{\cos t\text{ price}}*100 \\ \text{percentage decrease = }(4.5)/(49.50)*100 \\ \text{percentage decrease = }(450)/(49.50) \\ \text{percentage decrease =}9.09090909091 \\ 9.09090909091\approx9.1\text{\%} \end{gathered}`