Question

What is the vertex of the quadratic function: y=-3(x+5)^2-4

Answer 1

V=(-5,-4)
to find the vertex you use V=-b/2a
y=-3(x+5)^2-4
which then turns to
y=-3x^2-30x-79
a=-3
b=-30 x=30/2(-3)
x=30/-6
x=-5
plug x into the equation and solve for y =-3(-5)^2-30(-5)-79
y=-4
x=-5 y=-4 Vertex=(-5,-4)