Question

When landing after a spectacular somersault, a 40.0 kg gymnast decelerates by pushing straight down on the mat. calculate the force she must exert if her deceleration is 7 times the acceleration of gravity?

Answer 1

The force of the gymnast on the mat comes from the second law of physics

`F=m*a` where the acceleration is given as

`a=7*g =7*9.81 =68.67 (m/s^2)`
Therefore the force is

`F=40*68.67 =2746.8 N`