Question

An astronaut on another planet drops a 1-kg rock from rest and finds that it falls a vertical distance of 2.5 meters in one second. on this planet, the rock has a weight of: (hint: use d= 1/2 g t^2 to find g; then use w = mg to find weight.)

Answer 1

x=.5(a)t^2 can be used: 2.5m=.5(g)(1), g=5m/s^2. 

Answer 2

Weight = 5 N

Step-by-step explanation:

As we know that rock falls a distance of 2.5 m in one second so now we can use kinematics to find the acceleration of the rock

`d = (1)/(2)gt^2`

here we know

d = 2.5 m

t = 1 s

now from above equation we know

`2.5 = (1)/(2)g(1)^2`

`g = 5 m/s^2`

So here the weight of the rock is given as

`W = mg`

`W = 1* 5`

`W = 5 N`