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If p = .9, what is the frequency of the heterozygote? .81+(2)(.9)(.1) + (.01) .10 .81 + .18 .18
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If p = .9, what is the frequency of the heterozygote? .81+(2)(.9)(.1) + (.01) .10 .81 + .18 .18

User Thomas Taylor
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Write down the Punnett square to find the frequencies:

R(.9) r(.1)
R 0.81 0.09
r 0.09 0.01

The answer choices given are confusing. I'll let you figure out the choices.
User Gembird
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