Question

Kevin and randy Muise have a jar containing 41 coins all of which are either quarters or nickels . The total value of coins in the jar is 7.45 how many of each type of coin do they have

Answer 1

To find the number of quarters and nickels, we can set up a system of equations using the total number of coins and the total value of the coins. Solving this system of equations, we find that Kevin and Randy have 27 quarters and 14 nickels.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's use the variables q (number of quarters) and n (number of nickels). We know that there are a total of 41 coins, so we can write the equation q + n = 41. We also know that the total value of the coins is $7.45, so we can write the equation 0.25q + 0.05n = 7.45.

Now we can solve this system of equations using substitution:

1. Isolate one variable in one of the equations. Let's isolate q in the first equation: q = 41 - n.
2. Substitute this expression for q in the second equation: 0.25(41 - n) + 0.05n = 7.45.
3. Simplify and solve for n: 10.25 - 0.25n + 0.05n = 7.45. Simplifying further, we get 0.20n = 2.80. Dividing by 0.20, we find that n = 14.
4. Substitute this value of n back into the first equation to find q: q = 41 - 14 = 27.

Therefore, Kevin and Randy have 27 quarters and 14 nickels in their jar.

Answer 2

0.25x+0.05=7.25
x+y=41

im not gonna tell you the answer but thats how you get the answer