Question

Factor 3/4 out of 3/4z + 6

Answer 1

ANSWER


`(3)/(4) z + 6 = (3)/(4) (z + 8 )`


Step-by-step explanation

We want to factor

`(3)/(4)`
out of


`(3)/(4) z + 6`

The first term is already having a factor of

`(3)/(4)`
The constant term which is the second term is not having a factor of

`(3)/(4)`
so we need to use a trick of multiplying and dividing by the same factor to obtain,




`(3)/(4) z + 6 = (3)/(4) z + (3)/(4) * (6)/( (3)/(4) )`


We can now factor

`(3)/(4)`
out of the right hand side to obtain,


`(3)/(4) z + 6 = (3)/(4) (z + (6)/( (3)/(4) ) )`
Let us rewrite the right most fraction using the normal division symbol.


`(3)/(4) z + 6 = (3)/(4) (z + 6 / (3)/(4) )`




We simplify to obtain,


`(3)/(4) z + 6 = (3)/(4) (z + 6 * (4)/(3) )`



This further gives us,



`(3)/(4) z + 6 = (3)/(4) (z + 2 * 4 )`




`(3)/(4) z + 6 = (3)/(4) (z + 8 )`