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When the expression -5x^2+20x-17 is written in the form $a(x+d)^2+e$, where a, d, and e are constants, then what is the sum a+d+e?

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1 Answer

7 votes
Solution by completing the square.

-5x^2+20x-17
=-5(x^2-4x)-17
=(-5(x-2)^2+20) -17
=-5(x-2)^2+3
So a=-5, d=-2, e=+3
a+d+e=-5-2+3=-4
User Ken Beckett
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