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Solve for first two positive solutions sin(3x)cos (4x)+cos(3x)sin(4x)=-0.9

Solve for first two positive solutions sin(3x)cos (4x)+cos(3x)sin(4x)=-0.9
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1 vote
Solve for first two positive solutions sin(3x)cos (4x)+cos(3x)sin(4x)=-0.9

User Oliver Burdekin
by
8.9k points

1 Answer

7 votes
sin(3x)cos (4x)+cos(3x)sin(4x)=-0.9
Then sin(3x+4x) = 0.9
sin(7x) = 0,9
Arcsin(,9) = 64.158 degrees or 115.842
x = 9.165 and 16.549
User Kelvin Zhao
by
7.9k points
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