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5 votes
How much force is produced by a 1000 kg elevator falling freely at 9.8 m/sec/sec?

A. 0.0098 N
B. 980 N
C. 9,800 N
D. 102 N

1 Answer

5 votes
F = m x a
F = 1000 x 9.8
F = 9800 N

so the answer is c
User Chela
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