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A heavy crate applies of 1500 N on a 25-m^2 piston . The smaller piston is 1/30 the size of the larger one . what force is needed to lif the crate

User Gustavo
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2 Answers

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I don't know the name, but the opposite of gravity, if that helps!

User Wonce
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Answer:

The force needed to lift the crate is 50 N

Step-by-step explanation:


P_(1) = (F_(1))/(A_(1)) = (1500N)/(25 m^(2) ) \\P_(1)= P_(2) \\P_(2) = (F_(2))/(A_(2))\\A_(2) = 25*(1)/(30) \\(1500N)/(25 m^(2) ) =(F_(2) )/((25)/(30)m^(2)  )\\ F_(2)* 25 m^(2) = 1500 N *(25)/(30)m^(2)\\ F_(2)= (1250 N*m^(2))/(25 m^(2))\\ F_(2)= 50 N

User Csano
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